63x2+76x+21 = 0
(7x+3)(9x+7) = 0
x = -3/7 or x = -7/9
mc squared
Yes an area problem must have an squared unit. Suppose: Find the area of a suare with side 8 cm. Thus, 8 squared will be 64cm. Your answer will be 64 squared cm.
Cut the diameter in half.
what you do is First Outside Inside Last for example (m+5)(m+8) is m squared+8m+5m+40 and the answer is m squared+13m+40
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared
mc squared
They are like terms and can be added together as 11x squared
You multiply it and your finding space of what it has. The multiplication makes the squared.
yes
mc squared
what does5 squared look like in a algebraic problem
12 squared.
Yes an area problem must have an squared unit. Suppose: Find the area of a suare with side 8 cm. Thus, 8 squared will be 64cm. Your answer will be 64 squared cm.
Since 2mn is a factor of 4m2n2, it is automatically the GCF of this problem.
Solve this problem -x squared -40x- 80 =0
Your Problem: X - 4 = ?Current Problem: 3 [squared] - 4 = ?How: When a numbered is squared, it means you multiply it against itself. So, 3 squared equals 3x3.3x3 = 9So, you would then take 9 and minus it by 4, which would than equal 5.Answer:3 [squared] - 4 = 5or9 - 4 = 5
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.