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Find the slope of the line of 2x plus 2y equals 7?

The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).


What are the solutions to the simultaneous equation of 3x plus 2y equals 5x plus 2y equals 14 showing work?

If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7


What type of lines are these x plus 2y equals 7 and 2x - y equals 7?

x + 2y = 7 2y = -x + 7 y = -(x-7)/2 => -x/2 + 7/2 2x - y = 7 -y = -2x + 7 y = 2x + 7 Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.


3y-x equals 0 and 2x plus 2y equals 7?

Multiply First equation by 2: 6y - 2x = 0Add second equation to this: 6y - 2x + 2x + 2y = 0 + 7Simplify: 8y = 7 so y = 0.875 and x = 2.625


What is the slope of the line 7x - 2y equals 14?

7x-2y = 14 -2y = -7x+14 y = 3.5x-7


X plus 2y equals 8 2x plus y equals 7?

Sum Numb!


3x plus 2y equals 7 2x plus 4y equals 18?

(-1, 5)


X plus 2y equals 7 and 2x plus y equals 8?

(3, 2)


3x plus 2y equals 7 and 2x plus 4y equals 18?

(-1, 5)


How do you solve x plus 2y equals 4 y equals 2x plus 7?

x + 2y = 4 (A) y = 2x + 7 (B) 2*(B) gives: 2y = 4x + 14 Substitute the right hand side for 2y in (A) to give: x + (4x + 14) = 4 Simplify: 5x + 14 = 4 Subtract 14 from both sides: 5x = -10 Divide both sides by 5: x = -2 Substitute for x in (B): y = 2*(-2) + 7 = -4 + 7 = 3 Solution: (x, y) = (-2, 3)


What is the ordered pair for 2x plus 5y equals 16 plus -5x minus 2y equals 2?

2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)


-2x plus 14 equals 0?

If -2x +14 = 0, -2x = -14, or x = 7.