2x - 4x + 3 = 0 -2x + 3 = 0 2x = 3 x = 3/2 = 1.5
x2 - 2x - 13 = 0 x2 - 2x + 1 = 14 (x - 1)2 = 14 x - 1 = ±√14 x = 1 ±√14 x ≈ {4.742, -2.742}
2x-3=4x+9 -2x-12=0 2x=-12 x=-6
2x^2 + 8x + 3 = 0
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
x=0
x = 0
2x = -7 - 8y
-2x+16 = 0 -2x = -16 x = 8
Assuming that 4x2+2x = 0: 2x (2x+1) = 0 2x = 0 or 2x+1 = 0 x = 0 or -1/2
many solutions
y= -2x
2x + 2x + 146 + 26 = 172 4x + 172 = 172 4x = 0 x = 0
(2x + 3)(2x + 3)
2x+3-7=0 2x=4 x=2
X should be zeroas:X + 5 = 2X + 5so, 2X - X = 0 or X = 0
2x - 4x + 3 = 0 -2x + 3 = 0 2x = 3 x = 3/2 = 1.5