The values are: x = -6 and y = 10
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
This means that 2y - 3 = 2y + 4 which is not possible.
x-2y+bz=3 ax+2z=2 5x+2y=1 find values of a and b for which the system of linear equation has infinitely many solutions
2y+26 = 28 2y = 28-26 2y = 2 y = 1
The values are: x = -6 and y = 10
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
This means that 2y - 3 = 2y + 4 which is not possible.
x-2y+bz=3 ax+2z=2 5x+2y=1 find values of a and b for which the system of linear equation has infinitely many solutions
No 2y-3 is not equals y plus 2AND how old are u?
(3, 2)
2y+26 = 28 2y = 28-26 2y = 2 y = 1
-2y=x+8 is the answer
2y(x+2)=
This equation is unsolvable without knowing one of the values of either x or y.
Exactly (2y + 4) .
x = 11 - 2y and 14 - 2y. This means that 11 = 14. Is there a typo in the question?