0
f'(x) = (x2 - x)1/2
1. Add one to the exponent
2. Divide step 1 by the exponent plus one
= (x2 - x)1/2+1
____________
1/2 + 1
= (x2 - x)3/2
_________
3/2
= (2/3) (x2 - x)3/2 + C
It may also be written:
[2(x2 - x)3/2 / 3] + C
Check:
f(x) = (2/3) (x2 - x)3/2
Using the chain rule:
f'(x) = (2/3) (3/2) (x2 - x)3/2-1
= (x2 - x)1/2
Add your answer:
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