1 ft = 12 in
Using Pythagoras:
diagonal² = side² + side² = 2 × side²
→ side² = diagonal² ÷ 2
→ side = diagonal ÷ √2
perimeter = 4 × side
= 4 × diagonal ÷ √2
= diagonal × 2√2
= 3 ft 9 in × 2√2
= 3 × 12 + 9 in × 2√2
= 45 in × 2√2
≈ 63.6 in
= 5 × 12 + 3.4 in
= 5 ft 3.4 in
Approximately 10 inches.
Approximately 17 feet.
The perimeter = 12 feetthen the square diagonal = 12/4 = 3 feet The diagonal2 = 3x3 + 3x3= 18 feetThe diagonal = square root of 18 = 3x 21/2 feet = 3 x 1.4142 = 4.2426 feet
Using Pythagoras' theorem it is about 4.243 feet rounded to 3 decimal places
15 times the square root of two, all over two A formula is this: The diagonal for a square is always the sides of the square times the square root of 2
Given a 56 cm diagonal, the square will have a perimeter of 158.4 cm
Diagonal of a square of side s is given by: d = 21/2s We have, d = 13 inches So, using the above formula we get, s = d/21/2 = 13/21/2 inches = 9.193 inches
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
The perimeter of this square is 56.569 meters.
Using Pythagoras' theorem: 162+122 = 400 and the square root of this is 20 (the diagonal) Therefore: 16+12+20 = a perimeter of 48 inches
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm
The perimeter is 40 inches.