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Q: What is the approximate surface area of a regular tetrahedron with edge length 10 cm?

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A regular tetrahedron, with edges of length 1 units, has a total surface area of sqrt(3) square units.

Not necessarily. If all faces are equilateral triangles (all edges are equal length) then it is a regular polyhedron.

If the area of the base of the tetrahedron is A square units and the vertical height is h units, then the volume is V = 1/3*A*h cubic units. If the tetrahedron is regular, with sides of length of length s units, then V = sqrt(2)/12*s3 cubic units.

the five regular (same side length and angle measure) solids- dodecahedron, tetrahedron, cube, octahedron, icosahedron

The ratios are "small to large".

given the length of a side as S, the volume is: SQRT(2)*S3/12 Where SQRT(2) is the square root of 2 (~1,414) and S3 is the length of a side cubed.

Surface area of the pyramid: 4*0.5*144*sin(60) = 249 square cm to 3 significant figures

The approximate length multiplied by the approximate width.

The approximate length in adult human is 30 feet

approxamittly 25cm

What railroad

15 cm is a measure of length and a length has no surface.

have they changed the length of regular sized cigarettes

Specifications say: Standard/Regular (length) - 20.5 gallons Optional/Extended - 25.5 gallons Note: these are approximate.

50 miles

350 microns

the answer is 2,321 miles

16 feet

2,300 miles

7516.6 km.

32

17

A surface that has length and width.

60,000 miles

60,000 miles