If the figure is a rectangle then it is:- 18*35 = 630 square units
The length of a triangle with a height of 12 inches and an area of 18 square inches is 3 inches, since area is 1/2 * base * height. Therefore, 2 * area divided by height = 2 * 18 /12 = 3
3
18 square inches
The area of a triangle is (1/2) x (length of the base) x (height of the triangle). You ought to be able to handle it from this point.
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
Answer: 9 in Area is 1/2 base x height So 18 = 1/2 b x 4 That means the base is 36/4 or 9
6 centimetres( to find surface area one must multiply height by height, width by width and length by length. Then you must add the products together and you get the surface area. To get the side lengths from a surface area you must reverse and divide it by 3[height,length and width]. In your case that would be 18. Then you must find a number that when multiplied by 3 equals the quotient of the first division{18} and there you have it 6). This only works on cubes.
18 + 8 + 4 = 23
The first is clearly not a suitable triangle.
Area = ½base x height = 18; h = 4b, so b/2 x 4b = 18 ie 4b2 = 36making b2 = 9 and b = 3 inches
A cone with a diameter of 18km and a slant height of 20.1km has a total surface area of about 822.78km2
Square footage is length times height. In this case measure the entire length around the room and multiply it by the height of the wall. (15 + 18 + 15 + 18) x 15 = You do the math.