Area = pi * diameter * diameter /4 = 3.14 * 1 *1 /4 = approx = 3/4 of square inch
The diameter of a hexagon will be any segment that joins two vertices of the hexagon and passes through its center. Since each of the angles of a hexagon is 120 degrees, than any triangle, which is formed by one side of the triangle and two radii, is an equilateral triangle, and so the lengths of radii are also 16 inches. Thus, the diameter (the sum of two radii) is 32 inches.
The length of on side of an equilateral hexagon is half the diameter of the circumscribing circle.
To me, "one-inch-circle" sounds like one inch IS the diameter.
A bullet from a revolver is less than one inch in diameter and is a projectile.
Three 0.50 inch diameter pipes will fit into one 1.50 inch diameter pipe (hypothetically). The 0.50 inch diameters stack on top of each other until you have 1.50 inches!
If it is a regular hexagon then make 6 triangles then find the area of one then multiply by 6.
In a circle, Area = pi times radius squared: A = (pi)(r^2) Since the diameter equals 2 inches, the radius is one inch: A = (pi)(1^2) A = pi = 3.14 inches squared
one inch is one inch; one inch dia refers to one inch diameter of a circle; it is still one inch
One inch metre could be the area equivalent to a rectangle whose sides are 1 inch and 1 metre respectively. This area is equivalent to 39.3701 square inches. So the question becomes one of finding the diameter of a circle whose area is 39.3701 sq inches and the answer is 7.08 inches.
6/8 of an inch
28.575mm