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Coordinates: (-1, 4) (3, 7) (5, 2) (-1, 4)

When plotted on the Cartesian plane its diagonals of 2 times square root of 10 and 8 Times Square root of 10 will intersect each other at right angles.

Area of the quadrilateral: 0.5 times the product of its diagonals = 80 square units

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Q: What is the area of a quadrilateral with coodinates at -1 4 and 3 7 and 5 2 and -5 -17?
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What is the area of the quadrilateral ABCD whose vertices are at -1 4 and 3 7 and 5 2 and -5 -17 giving the reason for your answer?

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