A rectangle measuring 3.2m x 10m has an area of 32m
A rectangle measuring 3.2m x 10m has an area of 32m.
The area of a square that has a perimeter of 32m is: 64 m2
You mean 32m width and height? Cuz you need to know both to get the area. You just multiply them together. If your height is 32m and your width 32m then area would be 1024m, it's simple math.
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32m. Area_of_square = side2 -> side = √area -> side = √64m2 = 8m Perimeter_of_square = 4 x side -> Perimeter = 4 x 8m = 32m
No you dont you multiply using area for example: A=LxW 4mx8m A=32m
A trapezoid does not have three bases!
If: 8m = 32m+96 Then: m = -4
ind the area of the rhombus if AE = 20 m and DE = 32 m.
Approx. 33.5 m To solve you use Pythagorean Theorem: c2 = a2 + b2 , where c is the hypotenuse of the right triangle. In this case c will be the length of the guy wire. The length of one leg of the triangle will 10m and the other will be 32m (40m - 8m) So, c2 = (10m)2 + (32m)2 c2 = 100m2 + 1024m2 = 1124m2 c = SQRT (1124m2) or c = 33.53 m
To work out the area of a triangle, you use the equation, 1/2 base * height... So in this scenario, the area would be: (25m / 2) * 32m = 400m2
32m