Area is 8x+16.
The dimensions of a rectangle are the length and the width. With these two measurements , the area of the rectangle can be calculated : Area = length x width. The perimeter can also be found : Perimeter = (2 x length) + (2 x width).
A rectangle can have only 2 dimensions and so finding the area from the given 4 dimensions has many possibilities.
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
It depends on the rectangle, but in any case, a rectangle is a 2-dimensional figure so it cannot have measurements in 3 dimensions!
The area of rectangle is : 8.0
The dimensions of a rectangle are the length and the width. With these two measurements , the area of the rectangle can be calculated : Area = length x width. The perimeter can also be found : Perimeter = (2 x length) + (2 x width).
A rectangle can have only 2 dimensions and so finding the area from the given 4 dimensions has many possibilities.
-1
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
6x2+19x+10 = (2x+5)(3x+2) Length = 2x+5 Width = 3x+2
It depends on the rectangle, but in any case, a rectangle is a 2-dimensional figure so it cannot have measurements in 3 dimensions!
The area of rectangle is : 8.0
2
2
2ab = area The sides of this rectangle are, a * sqrt(2) and b * sqrt(2) The equation of the ellipse reduces to, 0.5 + 0.5 = 1 Greetings, Dim Leed
Area of a rectangle= length x height.For example:A 2' by 4' rectangle would have an area of 2 x 4 = 8 square feet.As a formula, it is L*W=A.
If you mean area, then, the area of a rectangle is width * height. So...50cm^2.