0
What is the area of a rectangle that has a perimeter of 200 and a width of x?
Wiki User
∙ 16y ago
AREA = L * W
You know that "W" is the width. So all you need is the length. The parimeter of any rectangle is two widths (2W) plus two lengths (2L). So, in other words:
2W + 2L = 200.
But we only need one of each, so we divide the perimeter by "2" to determine what one width and one length would be:
L + W = 100.
Now that we know that, one length (the missing part of our equation) is:
L = 100 - W
Put it all together, and we get:
AREA = L * W
AREA = (100 - W) * W
Wiki User
∙ 16y ago
Add your answer:
Earn +20 pts
The perimeter of a rectangle is 200 inches the length exceeds the width by 96 inches?
Length + width = half perimeter = 100". Length is 98", width is 2"
What is the perimeter of 24cm by 100cm?
248cm. Why? Because it is a rectangle so the perimeter is length + length + width + width or just widthx2 + lengthx2. So, 24x2=48 and 100x2=200. 200+48=248cm.
If 2 rectangles have the same area must they have the same perimeter?
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
What is 200 feet by 240 feet in area and perimeter?
A rectangle measuring (200-ft x 240-ft) has Area = 48,000 square ft Perimeter = 880 ft
The width of a rectangle is half as long as the length the rectangle has an area of 200 square feet what are the length and width of the rectangle?
Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft
If you have a rectangle whose Perimeter equals 60 and the Area equals 200 what are the lengths of the four sides?
The rectangle must have sides with lengths of 20, 20, 10, and 10. 20+20+10+10 = 60 (perimeter) 20*10 = 200 (area)
What is the area of a rectangle measuring 25 feet long by 8 feet wide?
The area of rectangle is : 200.0
Can you calculate the area if you know the perimeter?
No, you can not calculate an area if you know just the perimeter. For example, rectangle with sides of 10 and 20 would have a perimeter of 60 and an area of 200, but a square of sides 15 would have a perimeter of 60 and an area of 225. You need to know more details about the shape than just the perimeter.
Jim has designed a rectangle with an area of 100 square feet and a perimeter of 401 feet is it possible that Jim's rectangle has whole number side lengths?
No it is not possible the dimensions are 200 by 1/2
The length of a rectangle is 100cm what is the width of the rectangle if the perimeter is 6 times the width?
P = 2(100 + W) and P = 6W so 200 + 2W = 6W making 4W = 200 so W = 50 cm.This suggests that in any rectangle with a length twice the width, the perimeter is 6 times the width. eg 56 x 28: 56 + 28 = 84 x 2 = 168 = 6 x 28.Simple proof: P = 2 (L + W) but L = 2W so P = 2 (2W + W) = 2 x 3W = 6W. QED
How much will it be to fence an area of 1600 sq ft at 8per ft?
Assuming the area is a rectangular plot, it will cost $16,000. Area is calculated by multiplying length by width, so Area = Length x Width In this particular case, we know the area is 1600 ft2. We can then assign any number less than that to either the length and width, and solve for the other value. I'll assign the length a value of 200 ft. 1600 ft2 = 200 ft x Width To find width, we divide both halves of the equation by 200 ft. This tells us that the width of the plot we're talking about has to be 800 ft. To figure out how much fencing we need, we need to find the perimeter of the plot we're discussing. The equation for perimeter of a rectangle is 2 x Length + 2 x Width Or in our case 2 x 200 + 2 x 800 400 + 1600 2000 ft. At $8 per foot of fencing, that's 2000 * $8, or $16,000
The length of a new rectangle playing field is 8 yards longer than quadruple the width If the perimeter of the rectangle playing field is 496 yards What are its dimensions?
The length is 200 yards and the width is 48 yards.length + width = 248 yards, and length = (4 x width) + 8 yards.substituting (4 x width) + 8 yards for length,(4 x width) + 8 yards + width = 248 yards;simplifying, width = 240/5 yards = 48 yards;then length = 248 - 48 yards = 200 yards
