It is: 0.5*8*10 = 40 square feet
70 ft
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
two sides 12 ft and two sides 10 ft is 120 sq ft (12*10)
A(rect) = w * l = 12ft*10ft = 120ft2Length * width = area10 * 12 = 120
70 ft
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
48 sq ft.
It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.
10ft 3in * 10ft 3 in = 10.25 ft*10.25 ft = 105.0625 sq ft.10ft 3in * 10ft 3 in = 10.25 ft*10.25 ft = 105.0625 sq ft.10ft 3in * 10ft 3 in = 10.25 ft*10.25 ft = 105.0625 sq ft.10ft 3in * 10ft 3 in = 10.25 ft*10.25 ft = 105.0625 sq ft.
30ft
its 10000 ft² its 10000 ft²
Just do the multiplication.
Assuming the shape is a triangle, the area is 11.40 sq ft, approx.
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
Area of a rectangle = (length) x (width) = 10-ft x 5-ft = 50 square feet