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The area of the rhombus is 40 square feet.

To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.

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Q: Area of a rhombus with diagonals of 8 ft and 10 ft?
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Related questions

What is the area of a rhombus diagonals of 8 ft and 10ft?

It is: 0.5*8*10 = 40 square feet


What is area of rhombus with diagonals of 8ft and 6ft?

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It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.


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What is area of rhombus with diagnols of 8 and 10 feet?

0.5*8*10 = 40 sq ft


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How many square feet in an area 48 feet by 10 feet?

Area = 48 ft * 10 ft = 48*10 sq ft = 480 sq ft.


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How many 10x10 areas are in 4000 square feet?

There need not be any as an area can have any shape; for example 4000 sq ft can be a rectangle with side lengths 1 ft and 4000 ft - as this rectangle has a width of 1 ft a 10 ft by 10 ft area cannot be extracted from it. However, if you are asking how many sections with the same area as a square of sides 10 ft can be made in an area of 4000 sq ft, then: 4000 sq ft ÷ (10 ft × 10 ft) = 4000 sq ft ÷ 100 sq ft = 40.


What is the area of a triangle that is 8 ft by 10 ft?

The area of triangle is : 40.0