The area of the rhombus is 40 square feet.
To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
It is: 0.5*8*10 = 40 square feet
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
0.5*8*10 = 40 sq ft
70 ft
Area = 10 square feet.
It is: 0.5*8*10 = 40 square feet
48 sq ft.
It is a rhombus with sides of length sqrt(61) feet = approx 7.8 feet.
Rhombus comprises 4 triangles which can be arranged to form 2 rectangles 5' x 6', so total area is 60 ft2.
0.5*8*10 = 40 sq ft
70 ft
Multiply the diagonals and divide by 2. So : 18 x 7 = 126 126 / 2 = 63 ft
Area = 48 ft * 10 ft = 48*10 sq ft = 480 sq ft.
Area = 10 square feet.
The area of a circle that has a 10 ft diameter is: 78.54 square feet.
There need not be any as an area can have any shape; for example 4000 sq ft can be a rectangle with side lengths 1 ft and 4000 ft - as this rectangle has a width of 1 ft a 10 ft by 10 ft area cannot be extracted from it. However, if you are asking how many sections with the same area as a square of sides 10 ft can be made in an area of 4000 sq ft, then: 4000 sq ft ÷ (10 ft × 10 ft) = 4000 sq ft ÷ 100 sq ft = 40.
The area of triangle is : 40.0