two sides 12 ft and two sides 10 ft is 120 sq ft (12*10)
12 x 10 = 120 square feet
A(rect) = w * l = 12ft*10ft = 120ft2Length * width = area10 * 12 = 120
Let x be the width of the rectangle. The length will therefore be x + 10 and the volume will be x(x + 10) = x2 + 10x The questuion gives the numeric value for the area as 264, so x2 + 10x = 264 => x2 + 10x - 264 = 0 => (x + 22)(x - 12) = 0 => x = -22 or x = 12. Since only a positive number can be used as a real length, the width of the rectangle is 12ft and the length is 12 + 10 = 22ft. So the dimensions of the rectangle are 22ft x 12ft.
120
The formula you need is: area = length x width Replace the numbers you know; solve for the number you don't know.
To find the area of a rectangle, multiply length x width: 12 x 10 = 120 sq ft
12 x 10 = 120 square feet
Area=length x width, A=lxw=10ft x 12ft=120ft2
A(rect) = w * l = 12ft*10ft = 120ft2Length * width = area10 * 12 = 120
56-ft
To find the area of a rectangle, multiply the length and width. 12ft * 7ft = 84 square feet
Length is 12ft, width is 4 ft. 2 x (length + width) = perimeter = 32 ft ⇒ length = 16ft - width [1] length x width = area = 48 sq ft Using [1] above: ⇒ (16ft - width) x width = 48 sq ft multiplying out and rearranging: ⇒ width2 - 16 x width + 48 = 0 factorizing: ⇒ (width - 4)x(width - 12) = 0 Thus width = 4 or 12, so using [1] above: ⇒ width = 4ft, length = 16 - 4 = 12ft or width = 12ft, length = 16 - 12 = 4ft Convention is that the length is larger than the width, thus rectangle is 12ft long by 4 ft wide.
Times the length by the width of a floor to find the area in square measurement.12ft x 10ft = 120sq ft (could be written thus: 120ft2)
To find the area of your rectangle, multiply 16ft by 12ft. This gives you 192. So your answer would be 192 square feet.
Let x be the width of the rectangle. The length will therefore be x + 10 and the volume will be x(x + 10) = x2 + 10x The questuion gives the numeric value for the area as 264, so x2 + 10x = 264 => x2 + 10x - 264 = 0 => (x + 22)(x - 12) = 0 => x = -22 or x = 12. Since only a positive number can be used as a real length, the width of the rectangle is 12ft and the length is 12 + 10 = 22ft. So the dimensions of the rectangle are 22ft x 12ft.
120
120