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Perimeter = 29 cm so each side is 7.25 cm.

The triangle formed by the diagonal and two sides has sides of 7.25, 7.25 and 11.8 cm so, using Heron's formula, its area is 24.9 square cm.

Therefore, the area of the rhombus is twice that = 49.7 square cm.

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Q: What is the area of a rhombus when one of its diagonals is 11.8 cm in length and has a perimeter of 29 cm showing work and answer?
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Is the diagonals of rhombus congruent?

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