The area of square is : 16.0
"i" is the square root of -1. Since there is no real number whose square is negative, i is an imaginary number.
Thirty seven and negative fifteen 37 and -15
No, but it is irrational, because there is no rational number whose square is two. Imaginary numbers are the square roots of negative numbers.
Yes, for example: square root of 2, and the negative of the square root of 2.
A vector is a quantity described by size and direction. Mathematically, the square of a vector is negative, e.g. i^2 = -1, thus a quantity whose square is negative is a vector, e.g. 5i is a vector because (5i)^2 = -25.
If you have not studied complex numbers, then the answer is as follows:The rules of multiplication for real numbers are thata positive times a positive is a positive, anda negative times a negative is a negative.[Also, 0 times 0 is 0].The upshot of all that is the square is never negative. And so, the answer is that there is no real number whose square is -62.If you have studied complex numbers then you should not be asking such basic questions! Still, the square roots of -62 are the complex pair ±7.874i where i is the imaginary square root of -1.
The area of square is : 11664.0
The square of any real number is non-negative. So there is no number whose square is negative. But there are times when it is mathematically helpful to be able to take the square root of a negative number. This is where i comes to the rescue. i is a number such that i2 = -1. Then, if you want to find the square root of -4, for example, -4 = 4*(-1) So that sqrt(-4) = sqrt[4*(-1)] = sqrt(4)*sqrt(-1) = +/- 2*i
The area of a square whose perimeter is 36 inches is: 81 square inches.
Bob Hope
First three answers are: 32 + 42 = 52 62 + 82 = 100 = 102 52+122 = 132 but there may be more options. Thanks Mohammed Haque
It could be a square whose sides are sqrt(1/3) of the original square or a rectangle whose length is the same as the side of the square but whose width is one third of that. There are many other possibilities.