If you put two of ANY triangle hypotenuse to hypotenuse the shape will have 4 sides (thus a parallelogram or quadrilateral).
The length of the hypotenuse works out as the square root of 41
Square root of 41
A right triangle that has one side 4 inches long and the hypotenuse 5 inches long must have the other side the square root of 52 - 42 which is 3. So if it was a rectangle the area would be 3 x 4 = 12 square inches. So the triangle will be half this are and thus 6 square inches. Another way would be to say base x 1/2 the height so 3 x 4/2 = 6 square inches.
Hmmm. the triangle you describe is HALF of a rectangle...
If you put two of ANY triangle hypotenuse to hypotenuse the shape will have 4 sides (thus a parallelogram or quadrilateral).
The length of the hypotenuse works out as the square root of 41
Square root of 41
A right triangle that has one side 4 inches long and the hypotenuse 5 inches long must have the other side the square root of 52 - 42 which is 3. So if it was a rectangle the area would be 3 x 4 = 12 square inches. So the triangle will be half this are and thus 6 square inches. Another way would be to say base x 1/2 the height so 3 x 4/2 = 6 square inches.
Hmmm. the triangle you describe is HALF of a rectangle...
Use Pythagoras' theorem: 42+42 = 32 and the square root of this is the length of the hypotenuse
Given the legs a and b of a triangle are 3 and 4, the hypotenuse is: 5
The Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. 1. squares, not square roots 2. right triangle, not isosceles 3. sides opposite the hypotenuse, not any two 4. What are the mistakes, not what is
the square root of 116
It would be the square root 32 in cm
Use Pythagoras' theorem:- 42+52 = 41 and the square root of this is the length of the hypotenuse.
That will depend on the length of the other leg but if both legs are 4 cm then by using Pythagoras its hypotenuse is the square root of 32