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A right triangle that has one side 4 inches long and the hypotenuse 5 inches long must have the other side the square root of 52 - 42 which is 3. So if it was a rectangle the area would be 3 x 4 =

12 square inches. So the triangle will be half this are and thus 6 square inches.

Another way would be to say base x 1/2 the height so 3 x 4/2 =

6 square inches.

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Q: What is the area of a right triangle that one the right side 4 inches long and the hypotenuse is 5 inches long?
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