The area of square with side of 7 inches is 49 sq. inches
A square must have sides of the same length. It is not clear how 11 inches AND 7 inches can both refer to one square.
Radius of the circle will be 7 inches and its area is pi*7^2 = 154 square inches rounded to a whole number
-- Perimeter = distance all the way around it = (5 + 7 + 5 + 7) inches -- Area = (5 x 7) square inches
7 square inches is the area in this case.
Perimeter: 7+3+7+3 = 20 inches Area: 7 times 3 = 21 square inches
If it's an equilateral triangle with 10 inch sides its height is about 8.66 inches and not 7 inches. So: area = 0.5*10*8.66 = 43.3 square inches Or: area = 0.5*10*10*sin(60) = 43.3 square inches to 1 decimal place
Perimeter = 2*(5 + 7) = 24 inches.Area = 5 * 7 = 35 square inches.
Length and side: 7 inches and 5 inches respectively
The area of square is : 49.0
Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches
Area of rectangle = Length * Breadth 126 = 18 * B => B = 126/18 = 7 inches.