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Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places.

If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches

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What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches?

I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.


What is the area of equilateral triangles with sides of 10 inches and heigth of 7 inches?

Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.


What triangle has sides that measure 9 in 9 in and 9 in?

If all three sides are 9 inches in length, then it is an EQUILATERAL Triangle. All the angles are 60 degrees.


What is the area of an equilateral triangle with sides of ten inches and height of seven inches?

There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.


What is the area of an equilateral triangle with side of 10 inches and height of 7 inches?

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches


What is the area of an equilateral triangle with sides of 10 inches and 7 inches?

By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!


What is the perimeter of a triangle which sides measure 6 inches?

18 inches and it is an equilateral triangle


What triangle has 3 sides that equal 4 inches?

An equilateral triangle...


What is the height of an equilateral triangle with the side lengths of 8 inches?

To find the height of an equilateral triangle, you can use the formula: height = (√3/2) * side length. For an equilateral triangle with side lengths of 8 inches, the height would be (√3/2) * 8 inches, which simplifies to approximately 6.93 inches. This height represents the perpendicular distance from any vertex to the opposite side in an equilateral triangle.


What is the area of an equilateral triangle with sides 8 inches long?

27.713 square inches.


What is the height of an equilateral triangle with sides of 20?

Height of an equilateral triangle = √3/2 x side = √3/2 x 20 = 10√3 ≈ 17.32


What height is an equilateral triangle with sides measuring 3cm?

Height of an equilateral triangle = √3 / 2 x side = (√3 / 2 ) x 3 = 2.598 cm.