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The area of triangle is : 4.0
Kamryn Renner
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How can it be proved that the circumradius of a triangle is the product of three sides divided by four times the area of the triangle?
We know that R = a/2sinA area of triangle = 1/2 bc sinA sin A = 2(area of triangle)/bc R = (a/2)*2(area of triangle)/bc R = abc/4*(area of triangle)
The three sides of a triangle is 2 and 3 and 4 what is the area of the triangle?
3 units2
What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
What is the of a triangle that has a base of 12'' and a height of 4''?
Area of triangle = 1/2 base times height1/2 * 12 * 4 = 24
What is the area of an equilateral triangle inscribed in a circle of radius 4cm?
Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.Two vertices of the triangle and the centre of the circle make a smaller equilateral triangle with legs of 4 cm and the included angle is 360/3 = 120 degrees.Therefore the area of each of these sub-triangles = 1/2*ab*sin(C) = 1/2*4*4*sin(120) = 1/2*4*4*1/2 = 4 cm2.And so the area of the inscribed triangle is 12 cm2.
If a triangle has an area of 16 and a base of 4 what is the height of the triangle?
area of triangle =(1/2)(base)(height) 16=(1/2)(4)h h=8
How can it be proved that the circumradius of a triangle is the product of three sides divided by four times the area of the triangle?
We know that R = a/2sinA area of triangle = 1/2 bc sinA sin A = 2(area of triangle)/bc R = (a/2)*2(area of triangle)/bc R = abc/4*(area of triangle)
What is the area of a triangle with the heght of 5 and the base of 4?
A triangle is half a square The area of a square is height × width(base) So, the area of a triangle is height × base ÷ 2 5×4÷2 = 10
The three sides of a triangle is 2 and 3 and 4 what is the area of the triangle?
3 units2
What is the area of a triangle with a base of 4 units and a height of 14 units?
area of a triangle = (base x height)/2 = (4 units x 14 units)/2 =28 square units
What is the area of a right triangle that is 4cm by 8cm?
The area of a right-angle triangle is half of the area of a rectangle 8cm x 4cm. Find the rectangle area and divide by half to find the area of the right-angle triangle. Therefore: 8 x 4 / 2 = 16cm2 * * * * * The above answer assumes that the two given lengths are the shorter legs of the triangle. It is, however, possible that these are the hypotenuse and one leg. In that case, the second leg is 4*sqrt(2) cm and the area of the triangle is 4 * 4*sqrt(2) / 2 = 8*sqrt(2) = 11.31 cm2.
Area of an equilateral triangle?
Area = side^2 x (√3)/4
How do you get the area of a triangle with 9 height and 4 base?
The formula for finding the Area of a Triangle is:Base X Height / 2= (9 X 4) / 2= 36 / 2= 18 u2
An isosceles right triangle has a hyptenuse of 4 What is the area of the triangle?
if hypotenuse is 4 then each side is 4 divided by sqrt 2 = 2.828 with two angles 45 degrees The triangle height is 2 so area is 1/2 base x height =1/2 times 4 times 2 = 4
What is the of a triangle that has a base of 12'' and a height of 4''?
Area of triangle = 1/2 base times height1/2 * 12 * 4 = 24
What is the area of a triangle with both sides 4?
1/2 *4 *4= 8
What is the area of a triangle that has a base of 4 inches and a height of 4 inches?
area of triangle = half (base*height) i.e. 1/2*(4*4)= 8 square inch.
