The area of an equilateral triangle is A=sqrt(3)*(l^2)/4, l is the length and A is the area multiply both sides by 4/sqrt(3) and get 4*A/sqrt(3)=l^2 take the square root of both sides and get l = sqrt(4*A/sqrt(3))
No because a rhombus has 4 sides whereas a triangle has 3 sides but they are both polygons.
No because a triangle has 3 sides whereas a parallelogram has 4 sides but they are both types of polygons
3 units2
No, because a triangle has no parallel sides.
With great difficulty - it is impossible without further information.For example:A triangle with sides 3, 4, 5 - base 3, height 4 has area 6 units2;a triangle with sides 2, 6, ~6.32 (√40) - base 2 height 6 has area 6 units2.Both the triangles have the same area but different sides; those are both right angled triangles, but other ones are possible, eg a triangle with sides 2.5, ~4.92 (1/2 x √97), 6 also has base 6 and height 2 and an area 6 units2.
Information about the lengths of two sides of a triangle is insufficient to determine its area.
Rectangle has 4 sides, and triangle has 3 sides. So they are similar, they both have sides - one has more than the other :)
No because they both have different properties inasmuch that a triangle has 3 sides whereas a trapezium has 4 sides.
Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
225(radical "3")/4
1/2*height*base = area 1/2*4/9*base = 5/6 square metres Multiply both sides by 2: 4/9*base = 5/3 Multiply both sides by 9: 4*base = 15 Divide both sides by 4 to find the length of the base: base = 3.75 metres Check: 1/2*4/9*3.75 = 5/6 square metres