Using the cosine and sine rules the area of the triangle works out as 457 square cm rounded.
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
area of a triangle is half the base times the height .5*22*28=308
If the two equal sides are each 22 units in length then using Pythagoras' theorem to find its height it works out as: 54.644 square units rounded to 3 d.p.
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
22
Assuming these are three sides of a triangle, the area is approx 440 square units.
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
area of a triangle is half the base times the height .5*22*28=308
If the two equal sides are each 22 units in length then using Pythagoras' theorem to find its height it works out as: 54.644 square units rounded to 3 d.p.
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
No. For a right angle triangle, the sum of the squares of the shorter sides equals the square of the longer side (the hypotenuse): 22 + 62 = 40 72 = 49
22
Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4Ratio of sides = 10/5 = 2 So ratio of surface area = 22= 4
132 according to siri
the height has to be 22
22
Let the length of the longest side of the triangle be x units.Since the lengths of the sides of the triangle are consecutive even numbers, which differ by 2, the perimeter of the triangle equals to (x - 4) + (x - 2) + x = 3x - 6.Since the length of the longest side is 22 units shorter than the perimeter, the perimeter of the triangle also equals to x + 22. So that3x - 6 = x + 22 (subtract x and add 6 to both sides)3x - x + 6 - 6 = x - x + 6 + 222x = 28 (divide both sides by 2)x = 14Thus the longest side has a length of 14 units.