Area of a triangle is 1/2*Base*Height. I believe you can take it from here.
The basic formula is: A = 1/2bh where A is area, b is the base of the triangle and h is the height Using trigonometry, the area of a triangle can also be expressed as: A = 1/2absinC, where A is the area, a and b are two sides of the triangle, and C is the angle between those sides.
Area 51.
when you multiply the area of the small triangle by four it equals the area of the large triangle.
A triangle with side a: 40, side b: 25, and side c: 25cm has an area of 300cm2
area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides
The area of triangle is : 340.0
The area of triangle is : 340.0
It depends on what you wish to measure: the lengths of sides, the angles, the area, the perimeter.
Given this area, the sides measure 52.92734 cm
It is: 0.5*25*20 = 250 square inches It doesn't matter whether or not a triangle is a right triangle; the area is always half of the base times the height.
Yes. The two equal sides would measure 3.
The two equal sides each measure 8 inches
A triangle with side a: 7, side b: 12, and side c: 11 units has an area of 37.95 square units.
Its not a triangle if it has only two sides.
If the sides of a triangle are doubled then the area becomes quadrupled (four times as large).
I am assuming that "traingle" is meant to be triangle and "permeter" is meant to be perimeter.The area of a triangle cannot be equal to its perimeter because the area is a measure in 2-dimensional space whereas a perimeter is a 1-dimensional measure. So their dimensions will always be different.Furthermore, the area of a triangle is not determined by its perimeter. The area of a triangle can be changed - without affecting its perimeter - simply by changing the angles.
Zero. The two shorter sides together make 70 metres, so they lie flat against the longest side. Really, there is no triangle. If the 3 sides actually make a triangle, you can use Heron's formula - look it up - to find the area.