answersLogoWhite

0


Best Answer

If it's an equilateral triangle with 10 inch sides its height is about 8.66 inches and not 7 inches.

So: area = 0.5*10*8.66 = 43.3 square inches

Or: area = 0.5*10*10*sin(60) = 43.3 square inches to 1 decimal place

User Avatar

Wiki User

11y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is the area of an equilateal triangle with sides of 10 inches and height of 7 inches?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches?

I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=Area of a equilateral triangle="root over of 3" /4 * "a square"Now I use this formula,where "a" is 10. So the answers come=43.3,which is 44.So the Correct answer is=44 inches.* * * * *Mostly correct, but:43.3 should be rounded to 43, not 44.The units for the area should be square inches, not inches.


What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches


What is the area of equilateral triangles with sides of 10 inches and heigth of 7 inches?

Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.


What is the area of an equilateral triangle with sides of ten inches and height of seven inches?

There is a problem with your question, namely that such a triangle does not exist. An equilateral triangle with sides of length 10 would have a height of 5 * (root 3), which is approx 8.66 (not 7 as the question states). An equilateral triangle of side length 10 inches would have an area of 25*(root 3), which is approx. 43.3 inches2.


What is the height of a triangle if area is 104 inches squared and the base is 13 inches?

Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches


What triangle has sides that measure 9 in 9 in and 9 in?

The triangle with sides measuring 9 inches, 9 inches, and 9 inches is an equilateral triangle.


What is the perimeter of the triangle that has sides 10 inches 8 inches 17 inches 21 inches?

A triangle cannot have four sides.


What is the area of an equilateral triangle with side of 10 inches and height of 7 inches?

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 Times Square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches


Given the sides of a triangle how do you find the height?

By using sides we get area of triangle and then using (1/2)heightxbase we get height.


Triangle ABC has two sides that measure 12 inches and 16 inches. which could be the measures of the corresponding sides of a triangle that is similar to triangle ABC?

One pair of corresponding sides of a triangle that are similar to triangle ABC are 6 inches and 8 inches. However, there are multiple answers to this question.


What is the perimeter of a triangle with sides of 3 in 5 in and 7 in?

The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter of the triangle with sides measuring 3 inches, 5 inches, and 7 inches is 3 + 5 + 7 = 15 inches.


What is the perimeter of a triangle which sides measure 6 inches?

18 inches and it is an equilateral triangle