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I'm showing it with absolute proof. Equilateral triangle both side are same in size & same angel.It's given with the sides of 10 inches & height 7 inches. I don't need to count the height(7),just use side(10).The formula is=

Area of a equilateral triangle="root over of 3" /4 * "a square"

Now I use this formula,

where "a" is 10. So the answers come=43.3,which is 44.

So the Correct answer is=44 inches.

* * * * *

Mostly correct, but:

  • 43.3 should be rounded to 43, not 44.
  • The units for the area should be square inches, not inches.

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6y ago
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9y ago

An equilateral triangle with sides of 10 inches cannot have a height of 7 inches.

An equilateral triangle with sides of 10 inches has a height of 8.66 inches

or

an equilateral triangle with a height of 7 inches has sides of 8.08 inches.

Decide which triangle you want and then resubmit your question.

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Q: What is the area of an equilateral triangle with sides of 10 inches and height of 7 inches?
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What is the area of an equilateral triangle with sides 10 inches and height of 7 inches?

Area of the equilateral triangle: 0.5*10*10*sin(60 degrees) = 25 times square root of 3 which is about 43.301 square inches to 3 decimal places. If it is an equilateral triangle with 3 equal sides of 10 inches then its height would be about 8.66 inches and not 7 inches


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What is the area of an equilateral triangle with side of 10 inches and height of 7 inches?

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If it's an equilateral triangle with 10 inch sides its height is about 8.66 inches and not 7 inches. So: area = 0.5*10*8.66 = 43.3 square inches Or: area = 0.5*10*10*sin(60) = 43.3 square inches to 1 decimal place