35.074 units2
The triangle with sides measuring 9 inches, 9 inches, and 9 inches is an equilateral triangle.
Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet
An equilateral triangle with sides of 9 meters, silly!
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
The area of a triangle is one-half the product of the triangle's base and height. The height of an equilateral triangle is the distance from one vertex along the perpendicular bisector line of the opposite side. This line divides the equilateral triangle into two right triangles, each with a hypotenuse of 9c and a base of (9/2)c. From the Pythagorean theorem, the height must be the square root of {(9c)2 - [(9/2)c]}, and this height is the same as that of the equilateral triangle.
The triangle with sides measuring 9 inches, 9 inches, and 9 inches is an equilateral triangle.
It will be 9 times as large. And that will be true for any plane shape, not just an equilateral triangle.
3.897 square inches.
Its area is 46.8 (46.76533) square inches.
Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet
An equilateral triangle with sides of 9 meters, silly!
If: (-2, 9) and (-7, -3) is the same distance then the height of the triangle is 13 units and each length of the equilateral triangle is 15.011107 units. Area = 0.5*13*15.011107 = 97.572 square units to 3 decimal places
Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
The area of a triangle is one-half the product of the triangle's base and height. The height of an equilateral triangle is the distance from one vertex along the perpendicular bisector line of the opposite side. This line divides the equilateral triangle into two right triangles, each with a hypotenuse of 9c and a base of (9/2)c. From the Pythagorean theorem, the height must be the square root of {(9c)2 - [(9/2)c]}, and this height is the same as that of the equilateral triangle.
6 squared = 3 squared + x squared if x is the height (altitude) of the triangle 36 = 9+x squared x squared =27 so x = 3 sqrt3 = 5.19615
Divide the base in half and draw the median from the apex. This median is also the altitude and so its length is the required height. Also, since it is the altitude, it forms a right angled triangle. Using Pythagoras on this triangle, the height is 9*sqrt(3)/2.
An equilateral triangle has three sides of equal length.