Use Pythagoras' theorem: 92-4.52 = 60.75 and the square root of this is the altitude which is 7.794 inches to 3 d.p.
Using Pythagoras' theorem its height works out as 17.321 inches rounded to 3 decimal places
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
The sides are 2*sqrt(3) units in length.
It is double the length of the base, in square units.
No. The altitude is smaller.
Given an altitude of 12 units, an equilateral triangle has side lengths of 13.9 (13.85641) units.
Using Pythagoras' theorem its height works out as 17.321 inches rounded to 3 decimal places
For the equilateral triangle in Euclidean space(i.e, the triangles you see in general) median is the same as its altitude. So, both are of equal length.
The perimeter of an equilateral triangle with a side length of 4 inches is 12 inches. Each side of an equilateral triangle is equal in length, so the perimeter is found by multiplying the side length (4 inches) by 3.
By definition, an equilateral triangle has all three sides of equal length! So it is impossible for it to have sides of length 10 inches and 7 inches!
Each side of the triangle is 16.16581 units in length.
Given side lengths of 8 units, an equilateral triangle will have an altitude of 7 (6.9282) units.
12 inches
With an altitude of 10 units, this triangle's sides each measure 11.55 (11.54701) units.
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?