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The perimeter of a rectangle gives only a maximum for the area, there is no minimum because the rectangle can be an infinitesimally thin but long rectangle with an area as small as you like.

The maximum area is attained when the rectangle is, in fact, a square.

So perimeter 12 => max area = 3*3 = 9 square units.

and perimeter 18 => max area = 4.5*4.5 = 20.25 sq units.

So the two can have the same area for any value in the range (0, 9].

You say 2?

Smaller rectangle = 0.3542 * 5.6458

and the larger = 0.2300 * 8.7720

If you want an area of S square units

then

smaller rectangle = 0.5*[6-sqrt(36-2*S)] by 0.5*[6+sqrt(36-2*S)]

and

larger rectangle = 0.5*[9-sqrt(81-2*S)] by 0.5*[9+sqrt(81-2*S)]

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Q: What is the area of two rectangles that have different perimeter which is 12 and 18?
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