A=B , A-B=B-B , A-B =0 B=C , B-B=C-B, 0=C-B So A-B=0 but also C-B=0 A-B=C-B ...add +b ...A-B+B=C-B+B , A=C
As A/B=C/D , So B=(A*D)/C
a - b = c -(a - b) = -c b - a = -c
2a. (a, b and c are all equal.)
This is true. As it is the same number for A and B so taking C from one would be the same as taking C from the other.
A.
As A/B=C/D , So B=(A*D)/C
a - b = c -(a - b) = -c b - a = -c
b = 40 - a, c = 42 - a so b + c = 40 - a + 42 - a, ie 82 -2a = 34 so a = 48/2 ie 24 b = 40 - 24 ie 16 and c = 42 - 24 ie 18
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
2a. (a, b and c are all equal.)
This is true. As it is the same number for A and B so taking C from one would be the same as taking C from the other.
A.
by transitive property
Yes.
a = 20 b = 60 c = 100
a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100
A=0 b=0 c=0