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Q: What is the argument that A equals B B equals C so A equals C?

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As A/B=C/D , So B=(A*D)/C

a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)

a - b = c -(a - b) = -c b - a = -c

2a. (a, b and c are all equal.)

A.

This is true. As it is the same number for A and B so taking C from one would be the same as taking C from the other.

b = 40 - a, c = 42 - a so b + c = 40 - a + 42 - a, ie 82 -2a = 34 so a = 48/2 ie 24 b = 40 - 24 ie 16 and c = 42 - 24 ie 18

by transitive property

Yes.

C equals A plus B under all circumstances; C= A + B.

yes

a = 20 b = 60 c = 100

Always.

A=0 b=0 c=0

a=24 b=16 c=18

The transitive property of equality says that if a=b, then b=c.If a=b and b=c, then a=cTo Prove:Using the equation:a=bsubstituting the value of b in terms of c:which is: b=ctherefore:a=ba=(c)a=c

7.5

a = 0.8

The Transitive Property of Equality.

a + b + c = 180 b = 3a c = 5a Substituting the values of b and c into the first equation. a + 3a + 5a = 180 or 9a = 180 so that a = 20 then b = 3a = 3*20 = 60 and c = 5a = 5*20 = 100

Ax + B = Bx + C Ax - Bx = (C - B) x (A - B) = (C - B) x = (C - B) / (A - B)

a + c - b = 3 + 2 - 5 = 5 - 5 = 0

Because there is no way to define the divisors, the equations cannot be evaluated.

If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18

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