If the average is 10 then 15 is 5 above average.
Average(5, 10, 15) = (5 + 10 + 15)/3 = 30/3 = 10
5 + 10 = 15. To take the average, add all the units to be averaged, then divide that number by the number of units, in this case, 2. So, 15/2 = 7-1/2 or simply, 7.5.
To find the missing number in the sequence 10, 15, 28, we can look for a pattern in the differences between the numbers. The difference between 10 and 15 is 5, and the difference between 15 and 28 is 13. If we assume a pattern in the differences, the missing number could be 21, which fits as the average of 15 and 28. Thus, the sequence could be 10, 15, 21, 28.
To calculate the average of a set of measurements, you sum all the individual values and then divide that total by the number of measurements. For example, if you have the measurements 5, 10, and 15, you would add these together (5 + 10 + 15 = 30) and then divide by the number of measurements (3), resulting in an average of 10. If you provide the specific set of measurements, I can help you calculate the average.
You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...You cannot. It should be their weighted average with the weights representing the number of observations in each average.For example, if 3 numbers have an average of 10 and 6 numbers have an average of 20, the combined average is not the average of 10 and 20 (which is 15).It is, in fact, (3*10 + 6*20)/(3 + 6) = (30+120)/9 = 150/9 = 16.66...
10 + 10 + 10 + 10 + 15 + 15 + 0 = 7070/7 = 10Average = 10
Well, honey, if you wanna find the number smack dab in the middle of -5 and 15, you just average those two bad boys. So, (-5 + 15) / 2 = 5. There you have it, sweet cheeks, 5 is the magic number that's halfway between those two extremes.
5+5 = 10 10+5 = 15 15-5 = 15 10+5 = 15
15
15
Average = 12
15. 5 - -10 = 5 + 10 = 15 → 15 + -10 = 15 - 10 = 5