1+2+3+5+5=11
11/5=2.2
The answer is 2.2 or 2 and 2/5.
It is: (1+5)/2 = 3
Yes, if you take 0 though 4. Average(0, 1, 2, 3, 4) = (1+2+3+4)/5 = 10/5 = 1
3^2 = 9 3 = 3 5^2 = 25 Average = all numbers added up, then divide the sum by the number of numbers available 9+3+25= 37 37/3= 12 1/3 12 1/3= Average of 3^2, 3, and 5^2.
The average of 3 numbers is their sum divided by the number of data in the data set (in this case 3). 2+-3+-4=-5. Their average is 5/3, or 1 2/3, or 1.6666666 with the 6 repeating.
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
The average is 2/3.---------------------2/3 + 1/2 + 5/6 = 4/6 + 3/6 + 5/6 = 12/6 =2.Divide by 3: 2/3.
It means the average of a group of numbers. For example... To find the average of the numbers 5 and 1, you would (1) add 5 and 1 and get 6, (2) divide your answer, 6, by the amount of numbers, 2 and (3) your average would be 3.
my daugter is a size 3 and she's 12... probally the average is 5
to get an average you add all the numbers up then divide by the number of numbers. like 1,2,3,4,and 5. would be 1+2+3+4+5=15/5=3. so 3 is the average
Add the numbers then divide by 3 1.5+2.5+1 = 5 5 divided by 3 = 1.6 therefore the average = 1.6
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
3 ÷ 2/5 = 3/1 ÷ 2/5 = 3/1 × 5/2 = (3×5)/(1×2) = 15/2 = 7½