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Q: What is the average of 8 numbers if their sum is 2464?

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Since there are 8 numbers, their average is 1/8 of their sum.

Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5

average is 9 so 8, 9 & 10

The average of nine numbers is 99, that is tha the sum of those numbers was 99 x 9, which is 891. The average of 8 numbers is 89, that is that the sum of those numbers was 89 x 8, which is 712. So, 891 - 712 = 179 The number that was deleted was 179.

If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.

The sum of the first 8 prime numbers is 77.

24/64 = 3/8

The fourth number is 10.

The average of a group of numbers is the sum of the numbers divided by the number of numbers. Because this is probably a homework problem, I won't give you the answer, but I can give you some help: #1) What is the sum of 10, 3, 8, 4 and 5? #2) How many numbers do you have? #3) Your answer will be the answer to #1 divided by the answer to #2.

The sum of the composite numbers that are less than 8 is: 4+6 = 10

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