If the sum of 5 = 28 then the average is 28 / 5 = 5.6
If the sum of the squares = 226 then the average is 226 / 5 = 45.2
From this information, and by a process of elimination, the numbers might be
1, 2, 6, 8 and 11.
There is no single formula.It is necessary to calculate the total sum of squares and the regression sum of squares. These are used to calculate the residual sum of squares. The next step is to use the appropriate degrees of freedom to calculate the mean regression sum of squares and the mean residual sum of squares.The ratio of these two is distributed as Fisher's F statistics with the degrees of freedom which were used to obtain the average sums of squares. The ratio is compared with published values of the F-statistic since there is no simple analytical form for the integral.
The sum of total deviations about the mean is the total variance. * * * * * No it is not - that is the sum of their SQUARES. The sum of the deviations is always zero.
1, 4 and 7
The F-statistic is a test on ratio of the sum of squares regression and the sum of squares error (divided by their degrees of freedom). If this ratio is large, then the regression dominates and the model fits well. If it is small, the regression model is poorly fitting.
It stands for sum of squares maybe? This is the sum of (observed value-mean value)^2 for all the observed values
The sum of their squares is 10.
Sum of squares? Product?
split 10 in two parts such that sum of their squares is 52. answer in full formula
The two numbers are 9 and 13.
Not unless at least one of the numbers is zero.
The middle number must be the average, so 681/3 = 227 and the other two numbers are 226 and 228.
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
The sum of the squares of the first 100 natural numbers [1..100] is 338350, while the sum of the first 100 natural numbers squared is 25502500.
85
There is no single number here. The two seed numbers are 5 and 6; their squares sum to 61.
5
88