The mean average of a set of numbers is the sum of the numbers divided by how many of them there are.
If there are 8 numbers with a sum of 2464, their mean average is 2464 ÷ 8 = 308.
Since there are 8 numbers, their average is 1/8 of their sum.
The average of nine numbers is 99, that is tha the sum of those numbers was 99 x 9, which is 891. The average of 8 numbers is 89, that is that the sum of those numbers was 89 x 8, which is 712. So, 891 - 712 = 179 The number that was deleted was 179.
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
average is 9 so 8, 9 & 10
The fourth number is 10.
96
Since there are 8 numbers, their average is 1/8 of their sum.
The average of nine numbers is 99, that is tha the sum of those numbers was 99 x 9, which is 891. The average of 8 numbers is 89, that is that the sum of those numbers was 89 x 8, which is 712. So, 891 - 712 = 179 The number that was deleted was 179.
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
If the sum of 5 = 28 then the average is 28 / 5 = 5.6 If the sum of the squares = 226 then the average is 226 / 5 = 45.2 From this information, and by a process of elimination, the numbers might be 1, 2, 6, 8 and 11.
average is 9 so 8, 9 & 10
Oh, dude, math time! So, the sum of the first four numbers is 15 x 4 = 60, and the sum of the last three numbers is 8 x 3 = 24. Add those together, you get 60 + 24 = 84. To find the average of all seven numbers, you divide 84 by 7, which gives you an average of 12. So, the average of all seven numbers is 12. Math wizardry!
The fourth number is 10.
The average of a group of numbers is the sum of the numbers divided by the number of numbers. Because this is probably a homework problem, I won't give you the answer, but I can give you some help: #1) What is the sum of 10, 3, 8, 4 and 5? #2) How many numbers do you have? #3) Your answer will be the answer to #1 divided by the answer to #2.
The sum of the first 8 prime numbers is 77.
To find six numbers with a mean (average) of 9, we can choose numbers such that their sum equals 6 multiplied by 9, which is 54. Here's one possible set of numbers: 10 10 9 9 8 8 The sum of these numbers is 54, and when you divide the sum by 6 (the number of values), you get the mean of 9.
The difference of two numbers is 8. Their sum is 22. What are the two numbers?