Assuming t is time, you need to know the distance traveled in time t. Then, divide the distance by time to obtain speed (velocity).
That depends upon what the object has done for the 20 seconds since t = 0 seconds.
Speed = 10/7 m/s
On a speed time graph, the distance can be calculated by working out the area underneath the line. To work out the distance travelled between t=0 and t=10 you would need to find these two values and then work out the area on the graph of the shape bound by the line of the particle, the x axis, t=0 and t=10. The average speed of the particle is the distance (calculated above) divided by 10.
Speed equals distance divided by time. S=D/T.
By using the formula distance equals rate times time or d = r x t
3 m/s
There is sufficient information to determine Jack's speed at t equals 10 seconds.
That depends upon what the object has done for the 20 seconds since t = 0 seconds.
Speed = 10/7 m/s
On a speed time graph, the distance can be calculated by working out the area underneath the line. To work out the distance travelled between t=0 and t=10 you would need to find these two values and then work out the area on the graph of the shape bound by the line of the particle, the x axis, t=0 and t=10. The average speed of the particle is the distance (calculated above) divided by 10.
To find the average velocity of a projectile, use V = D/T (Velocity equals Displacement over Time).
Speed equals distance divided by time. S=D/T.
By using the formula distance equals rate times time or d = r x t
Hundredweight in a Ton
Acceleration equals velocity divided by time i.e a=v/t The S.I unit of Acceleration is m/s2
d/t=s d = distance t = time s = speed the speed is actually going to be the average speed because they are practically the same thing (and for this equation speed is the exact same thing as average speed)
The bounds of integration are 10 and 20. The function that we are integrating is Q(t)=4(.96t)=3.84t. So the average value of Q(t) from 10 to 20 is equal to [1/(20-10)]*the integral from 10 to 20 of 3.84t dt. Simplifying, we get .384*the integral from 10 to 20 of t dt. Integrating, we get that the average value = .384(20^2 - 10^2)/2 = .196*(400 - 100) = .196 * 300 = 58.8. The average value in question is exactly 58.8 grams.