I have no idea what "axis stymies try" is.The question contains an expression: an expression cannot have an axis.
-1
It is at: (-1, 0)
y = x2 + 4 The graph is a parabola, with its nose at y=4 on the y-axis, and opening upward.
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
It is a parabola which doesn't touch the X-axis. i.e., It has no real roots.
There are none. For this equation, there is nonreal answer, as the graph of the quadratic does not pass below the x-axis
x2 + x2 = 2x2
x2 + y - 52 = 30x2 - x2 + y - 52 + 52 = - x2 + 30 + 52y = -x2 + 82Since a = -1, the parabola open downward, and crosses the x-axis at x = +&- sq.root of 82.0 = -x2 + 820 - 82 = -x2 + 82 - 82-82 = -x282 = x2+&- sq.root of 82 = x
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
Line of symmetry: x = 3