y=x2+2x+1 -b -2
2a= 2= -1
= axis of symmetry is negative one.
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
y-axis
It is the axis of symmetry.
It is x = 0.
Reflection about the y-axis.
Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
y-axis
An even function is a function that creates symmetry across the y-axis. An odd function is a function that creates origin symmetry.
It is the axis of symmetry.
It is x = 0.
Reflection about the y-axis.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
A function cannot have symmetry across the x-axis because such symmetry would violate the definition of a function, which requires that each input (x-value) corresponds to exactly one output (y-value). If a function were symmetric about the x-axis, for a given x-value, there would be two corresponding y-values (one positive and one negative), thus failing the vertical line test. Instead, a relation can exhibit x-axis symmetry, but it would not be classified as a function.
If the function, or channel, or whatever you are reffering to has a axis of symmetry across both the y-axis and the x-axis