y=x2+2x+1 -b -2
2a= 2= -1
= axis of symmetry is negative one.
y-axis
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
It is the axis of symmetry.
Reflection about the y-axis.
It is x = 0.
Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2
If a quadratic function has the points (-4,0) and (14,0), what is equation of the axis of symmetry?
y-axis
y = 2x + 2 + 4x+ 2 = 6x + 4 This is NOT a symmetric function and so there is no axis of symmetry.
An even function is a function that creates symmetry across the y-axis. An odd function is a function that creates origin symmetry.
It is the axis of symmetry.
Reflection about the y-axis.
It is x = 0.
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
If the function, or channel, or whatever you are reffering to has a axis of symmetry across both the y-axis and the x-axis
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
Line of symmetry: x = 3