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Q: What is the best order-of-magnitude estimate for 29300?

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It is tens of thousands.

1 ft = 0.3048 m (exactly)⇒ 1 m = (1 ÷ 0.3048 ) ft≈ 3.281 ft1 sq m = 1 m x 1 m≈ 3.281 ft x 3.281 ft≈ 10.764 sq ft⇒ to convert 29300 square meters to square feet multiply by approx 10.764.That's how to convert it, this is it beingconverted:⇒ 29300 sq m ≈ 29300 x 10.764 sq ft≈ 315383 sq ft.1 sq ft = 1 ft x 1 ft= 0.3048 m x 0.3048 m=

It is 60 as the best estimate for 57

The BEST estimate can only be 2852.831 anything else is not BEST.

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The best estimate of the number of stars in a typical galaxy is unknown there is so many but the best estimate is BILLIONS

There are 100 decilitres in one decalitre. Therefore, 293 decalitres is equal to 293 x 100 = 29300 decilitres.

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A best estimate is the best guess that you can give for an answer. It is not really done using a formula, just by comparing things in your mind.

The best estimate for the circumference of a circle that has a diameter of 6 is 18.9

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The best estimate is the true value.

Best estimate is 30 x 6 = 180 Actual answer is 192.34

To the nearest ten, 1240, 1050 and 980 respectively.

13.211...

no i can not

11.00

2.2360...

Since sqrt(52) is an irrational number, the best estimate is âˆš52. Any decimal estimate can be improved by adding another digit so none can be BEST.

31.8321

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