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The best estimate is 17.The chances are always the same:1/2

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Q: What is the best prediction possible for the number of times it will land on tails if you flip a coin 2 times?

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The number of sequences is 27 or 128.

Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.

Toss a coin 20 times and see what happens.It is POSSIBLE to always get 10 heads and 10 tails...but it is not very PROBABLE.

For 4 coin tosses, there are 16 possible outcomes. Tails on 75% of 4 tosses is 3 times tails, and 1 time heads. This occurs in 4 of those 16 possibilities, so the probability is 4/16 = 1/4 (or 25%). But if the question is 'what is the probability that it's tails at least 75% of the time, then you have to add in the 1 where all 4 are tails, then you have 5/16 (or 31.25%).

Half the time they will be the same, half the time they will be different. Half of the time that they're the same they will be heads, half the time they are the same they will be tails. It's your homework, YOU figure it out. The way I figure it. There are four options: 1) heads / heads 2) heads / tails 3) tails / heads 4) tails / tails By process of chance, one out of four times both coins will be heads/heads. Therefore 780/4 = 195 times.

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The outcomes are: heads, tails, tails or tails, heads, tails or tails, tails, heads. You can see that there are 3 possible outcomes with exactly 1 head.

Since the probability is 1/4, the number of times this will happen will likely be close to 68 divided by 4.

It depends on the definition of an outcome. If you care about the order of the tosses, <br /> you get 2 possible outcomes per toss. Three tosses give you 2*2*2=8 possible outcomes. If you only care about the final number of heads and tails, there are 4 possible outcomes (3 heads, 2 heads and a tail, a head and two tails, or 3 tails).

Let's call one coin A and the other B. omes The possible outcomes for the coins are; A heads and B tails, A tails and B heads, A and B heads, A and B tails. That's four outcomes. The possible outcomes for a single die (as in dice) are six since a die has six faces, So four times six is twenty four possible outcomes.

There are 4 possible outcomes. There are 2 outcomes (heads or tails) on the first toss and 2 on the second toss. The possibilities are HH, TT, HT and TH.

The number of sequences is 27 or 128.

Out of the 16 possible outcomes for a coin tossed four times, 4 of them result in 3 Tails & 1 Head. They are: TTTH, TTHT, THTT, and HTTT.

50%

For a regular cubic die, a reasonable point estimate is 5000.

There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.

Whenever you are trying to figure out the answer to an outcome problem, you just multiply how many sides it has by how many times you are tossing the coin.... 2 x 6 = 12 times.===================================Very reasonable. Warm, fuzzy, and intuitively satisfying. But, sadly, wrong.Every toss of a coin has 2 possible outcomes.If you write down the results of 6 tosses like: H T T H T H with an 'H' for each headsand a 'T' for each tails, the number of different patterns you could write down forsix tosses is2 x 2 x 2 x 2 x 2 x 2 = 64 .If you don't care about the sequence, and you just want to know how manydifferent splits of 'heads' vs 'tails' you could get in 6 tosses, then there are sevendifferent possible outcomes:-- no heads, 6 tails-- 1 heads, 5 tails-- 2 heads, 4 tails-- 3 heads, 3 tails-- 4 heads, 2 tails-- 5 heads, 1 tails-- 6 heads, no tails

Toss a coin 20 times and see what happens.It is POSSIBLE to always get 10 heads and 10 tails...but it is not very PROBABLE.