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(x - 1)(3x + 5)
3x+5y+8x+2y combine 3x and 8x to get 11x 11x+5y+2y combine 5y and 2y 11x+7y is the answer.
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
No. Y=3X2+1 is a Binomial Equation.
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
(3x+1)(2x+4)
(x - 1)(3x + 5)
-3x + 6 + 15x =11x + 8 ie -3x + 15x - 11x = 8 - 6 ie x = 2
3x+5y+8x+2y combine 3x and 8x to get 11x 11x+5y+2y combine 5y and 2y 11x+7y is the answer.
If you mean: (3x+1) and (2x+3) are factors of 6xsquared+11x+3 then yes they are
They are like terms and can be added together as 11x squared
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
No. Y=3X2+1 is a Binomial Equation.
x2+3x+8 is a trinomial But this quadratic equation will have no solutions because its discriminant is less than zero.
11x + 8 = 8x + 20 3x + 8 = 20 3x = 12 x = 4
3x2 - 11x - 4 = (x-4)(3 x + 1)
6y2+17y-14 = (2x+7)(3x-2) when factored