(4, 8)
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
-4
2x = 11x + 4 Subtract 11x from both sides: -9x = 4 Divide both sides by -9: x = 4/(-9) = -0.444...
It is: 3x+4
11x-7
The factors are -1(2x + 1)(3x + 4)
(4, 8)
x2 + 6x + 8 =(x + 2)(x +4)
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
2X^3 + 11X^2 = 6X 2X^3 + 11X^2 - 6X = 0 factor out an X X(2X^2 + 11X - 6) = 0 Now, for that quadratic equation I always go quadratic formula. Discriminant looks good for two real roots. X = -b (+/- ) sqrt(b^2-4ac)/2a a = 2 b = 11 c = - 6 X = - 11 (+/-) sqrt[11^2 - 4(2)(-6)]/2(2) X = - 11 (+/-) sqrt(169)/4 X = [- 11 (+/-) 13]/4 X = 0 X = 1/2 X = - 6
(2x-4)(x-1) = 0
3x2 - 11x - 4 = (x-4)(3 x + 1)
the answer is (3x-2)(9x squared+6x+4)
Dividend: 4x^4 -x^3 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
-4