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kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
1.0 kva
1hp = 735.5 watts 16,000 kVA / 735.5 = 21.754 hp
In what amount of time?
A kVA is basically the same as a kW - unless the so-called "power factor" is much less than one. However, it is quite often close to one, so it can be ignored. (Power = volts x amperes x power factor.)
Yes, a 3 phase 95 millimeter for each phase 150 meters long cable is enough for a 285 KVA genset.
It depends on the current, not the power. There is insufficient information in the question to answer it. Please restate the question.
35 KVA generator using for load 100 meter length which cable need to used
125
To answer this question the voltage of the genset is needed.
1.two part tariff= maximum demand+energy consumption (150 kva + any greater than 150 kva consumption) 2.three part tariff=maximum demand+energy consumption+ any energy charge (150 kva + any greater than 150 kva consumption + out source any energy charge ) unlimited usage of tariff is nothing but three part tariff
4core*240mm square..
It depends totally on the voltage used.
16mm2
It depends on the power factor, which depends on the reactance of the load.For a typical power factor of 0.92, 150 KVAR translates to 383 KVA, which translates to 352 KW.Power factor is the cosine of the phase angle (theta) between voltage and current. KVA times cosine (theta) is KW, while KVA times sine (theta) is KVAR.
A 10 mm cable is most commonly used for a 500 KVA transformer, 240 volt, 3 phrase. The size of the wire that is used in a transformer is based on the voltage.
Take the KVA and divide it by the voltage. 25/.230 = 109 amps. The transformer can put out up to 50% more that its rated for short durations. So you could get around 150 amps out of a 25 Kva tranformer in a worst case situation.