0
What is the centre and radius of a circle passing through the points of 2 2 and 1 1 and 7 -3 on the Cartesian plane showing work?
Wiki User
∙ 7y ago
General equation of a circle on the Cartesian plane: x^2+y^2+2gx+2fy+c = 0
Points: (2, 2) (1, 1) and (7, -3)
Substitute the above values into the general equation to form simultaneous equations
4g+4f+c = -8
2g+2f+c = -2
14g-6f+c = -58
Solving the simultaneous equations: g = -4, f = 1 and c = 4
Substituting the above values into the general equation: x^2+y^2-8x+2y+4 = 0
Completing the squares: (x-4)^2+(y+1)^2-16-1+4 = 0
So: (x-4)^2+(y+1)^2 = 13
Therefore centre of circle is at (4, -1) and its radius is the square root of 13
Wiki User
∙ 7y ago
Add your answer:
Earn +20 pts
What is the centre and radius of a circle passing through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane?
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
How many lines of symmetry does a circle in circle?
An infinite number, all passing through the centre.
What is the centre and area in cm of a circle whose circumference cuts through the points of 1 0 and 7 -6 and 7 0 on the Cartesian plane?
It works out that the centre of the circle is at (4, -3) on the Cartesian plane and its area is 56.549 square cm rounded up to three decimal places.
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What is the centre and radius of a circle passing through the points of 6 3 and -5 2 and 7 2 on the Cartesian plane?
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
What is the centre and radius of a circle passing through the points of 5 5 and 8 5 and 5 1 on the Cartesian plane?
Using the formula of x^2 +2gx +y^2 +2fy +c = 0 it works out that the centre of the circle is at (6.5, 3) and its radius is 2.5 units in length. Alternatively plot the points on the Cartesian plane to find the centre and radius of the circle.
What is the centre and radius of a circle enscribed through the points of 6 2 and 8 -2 and 0 2 on the Cartesian plane?
It works out that the circle's centre is at (3, -2) and its radius is 5 on the Cartesian plane.
How do you mark equidistant points on circle?
It is the radius from the centre to the circumference or the diameter passing through the centre to both sides of the circumference
When a ray of light passing through a point in a lens does not undergo deviation?
When it passes through optical centre.
Is the equator the highest mountain?
No it is not a mountain. It is an imaginary line passing through the centre of the earth.
How many lines of symmetry does a circle in circle?
An infinite number, all passing through the centre.
What is the centre and area in cm of a circle whose circumference cuts through the points of 1 0 and 7 -6 and 7 0 on the Cartesian plane?
It works out that the centre of the circle is at (4, -3) on the Cartesian plane and its area is 56.549 square cm rounded up to three decimal places.
What is optical center of a lens?
optic centre is the geometrical centre of the lens the rays of light passing through this point emerges in the same direction without bending.
What is called optical center of a lens?
optic centre is the geometrical centre of the lens the rays of light passing through this point emerges in the same direction without bending.
What is the Cartesian equation of a circle whose centre is in the 1st quadrant with a radius of 7 and touches the x and y axes?
Centre of the circle is at (7, 7) and its Cartesian equation is (x-7)^2 + (y-7)^2 = 49
What is the radius of a circle and its centre that passes through the points of 5 0 and 3 4 and -5 0 on the Cartesian plane?
Points: (5, 0) and (3, 4) and (-5, 0) Equation works out as: x^2+y^2 = 25 Radius: 5 units in length Centre of circle is at the point of origin (0, 0) on the Cartesian plane.
What is the centre and radius of a circle passing through the points of 6 3 and -5 2 and 7 2 on the Cartesian plane?
Points: (6, 3) (-5, 2) and (7, 2) Circle's equation works out as: (x-1)^2+(y+3)^2 = 61 Centre of the circle is at: (1, -3) Radius of the circle is the square root of 61 which is about 7.81 to two decimal places
