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Points: (6, 3) (-5, 2) and (7, 2)

Circle's equation works out as: (x-1)^2+(y+3)^2 = 61

Centre of the circle is at: (1, -3)

Radius of the circle is the square root of 61 which is about 7.81 to two decimal places

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8y ago
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8y ago

Centre = (1, -3), radius = sqrt(61) = 7.81, approx.

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Q: What is the centre and radius of a circle passing through the points of 6 3 and -5 2 and 7 2 on the Cartesian plane?
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