An accurate answer requires elliptical integrals which is probably beyond the ability of many students with a university degree in mathematics!
A reasonably good approximation, due to Ramanujan, is
pi*[3*(a + b) - sqrt(10*a*b + 3*(a2 + b2)]
where a is the semi major axis = 24/2 = 12 feet
and b is the semi minor axis = 16/2 = 8 feet.
This gives P = 63.46 ft.
A quick an dirty way is as follows:
A circular pool of 16' diameter would have a perimeter of 16*pi = 50.27 ft
One with a 24' diameter would have a perimeter of 24*pi = 75.40 ft
The oval one would be roughly halfway between = 62.8 ft.
www.intheswim.com
If it is an elliptic oval, the circumference can be calculated by πab, where a and b are the lengths of the minor and major axes.
No, you cannot convert a round pool into an oval pool. The measurements would be off and you would be unable to move the pieces of the round pool to form an oval.
Its circumference.
You circumference anything that is round. (eg. A circle, and oval, etc.) -Hope this helps
Due to the differences in engineering and the parts involved, there really is no way to convert an oval above ground pool into a round pool.
If the pool is 26 feet around, then its circumference is 26 feet. If the pool is 26 feet across, then its circumference is 81.7 feet.
Most pools should be oval shaped. Oval shaped pools allow the swimmer to be able to swim laps and have a pool with greater depth.
It isn't possible to give a generalised formula for the circumference of an ellipse in terms of elementary functions. The circumference (or perimeter) of an oval is represented by an infinite series based on multiple aspects of the oval including: * Eccentricity * Implied length ("major radius") * Implied width ("minor radius")
To find the linear feet around an oval, you would typically calculate the circumference. The formula for the circumference of an oval is (a + b)π, where a and b are the semimajor and semiminor axes of the oval. In this case, for a 33x18 foot oval, the semimajor axis (a) would be 33/2 = 16.5 feet and the semiminor axis (b) would be 18/2 = 9 feet. Therefore, the circumference would be (16.5 + 9)π = 25.5π feet. This is approximately 80.07 feet.
Talledega, 2.66 miles in circumference
50.266