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If the pool is 26 feet around, then its circumference is 26 feet. If the pool is 26 feet across, then its circumference is 81.7 feet.

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Q: What is the circumference of a 26 ft round pool?
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What is the circumference of a round pool with a radius of 6 ft?

37 feet and 8.5 inches


What is the sq footage of a 26 round pool?

40 sq ft


How many feet of lights do I need for an 18 ft round pool?

fifty-six The circumference of an 18-foot circular swimming pool is: 56.55 feet


What is the circumference of 24' round pool?

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How many feet of lights do I need to go around an 18 ft round pool?

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What is the circumference of a 25 ft pool?

If the diameter is 25 feet then the circumference is 78.5 feet (approx).


How many yards is around a 24 ft round pool with a 2 ft edging around it?

The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.The circumference of the pool is 24 ft so its radius is 24/(2*pi) = 3.8 ft.Then radius of pool + edging = 3.8 + 2 = 5.8 ft.So circumference around edging = 36.6 feet = 36.6/3 = 12.2 yards.


What is the circumference of a pool if the radius is 3 feet?

6 pi ft


What is the circumference of a pool with the diameter of 22ft?

484/7 = 69 and one seventh ft


How do you measure perimeter of 18 ft round pool?

120


How many square feet in a 6 ft pool?

6 ft X 6ft pool would be 36 sq ft 6 ft round pool would be 28.26 sq ft


How many linear feet around 15 ft round pool?

If the 15 ft is the distance around the edge, then:Distance_round_edge = 15 ft If the 15 ft is the diameter of the round pool, then:Distance_round_edge = π x diameter = π x 15 ft= 15π ft≈ 47.12 ftIf the 15 ft is the radius of the round pool, then:Distance_round_edge = 2 x π x radius = 2 x π x 15 ft= 30π ft≈ 94.25 ft