The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
The x-intercept is (15 0)
x-intercept = (-6, 0)
The x intercept is when y = 0 ⇒ x + 5 x 0 = 15 ⇒ x = 15 ie the x intercept is 15.
They are at coordinates of: (0, -6) and (15, 0) respectively
2y = 4x + 3At the x-intercept, y=0.0 = 4x + 34x = -3x = -3/4The coordinates of the point are (-3/4 , 0)
5x - 2y = 20The x-intercept of a line is the point where its y-value is 0. When y=0, we get 5x = 20, or x=4. This means the coordinates of the x-intercept on this line are (4,0).
solve for x -x-2y=6 -x=2y+6 x=-2y-6 plug in y=0 x=-6 when y is 0 therefore the x intercept is (-6,0)
the x intercept is 3